3p^2=-25p-28

Solution for 3p^2=-25p-28 equation:

3p^2=-25p-28

We move all terms to the left:

3p^2-(-25p-28)=0

We get rid of parentheses

3p^2+25p+28=0

a = 3; b = 25; c = +28;
Δ = b2-4ac
Δ = 252-4·3·28
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-17}{2*3}=\frac{-42}{6}
=-7
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+17}{2*3}=\frac{-8}{6}
=-1+1/3
$